On a steeper slope, the jogger can run at an average speed of 5.3 miles per hour up the slope and 6.7 miles per hour going down the slope.
distance = rate times time.
In this problem, distance = 1 mile = rate times time
In the first case, the rate is 5.3 mph, so 1 mile= (5.3 mph)(time), and (time) =
1 mile
----------- = 0.189 hour
5.3 mph
In the second case, the rate is 6.7 mph, and
1 mile
----------- = 0.149 hour
6.7 mph
The total transit time (up and down) is 0.189 hour plus 0.149 hour, or
0.338 hour, or 20.3 minutes.