Answer:
option D is correct graph
Explanation:
![y+2>-3x-3](https://img.qammunity.org/2019/formulas/mathematics/middle-school/78eg06cb4d04vllooh7tcbasyf3piapnix.png)
Lets isolate y, subtract 2 on both sides
the inequality becomes
![y>-3x-5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/d08tnirj7ir3kpt0pvzrlvdqpl0ye2a4qk.png)
Now for graphing replace the inequality sign by = sign
![y=-3x-5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/4nw2y3a31sghh2hji5iiwcykl6fsuf4qo5.png)
LEts make a table
x y=-3x-5
-2 1
0 -5
1 -8
We have only > symbol , so we use dotted line for graphing the line
Now for shading use test point (0,0)
Plug in 0 for x and 0 for y
![y+2>-3x-3](https://img.qammunity.org/2019/formulas/mathematics/middle-school/78eg06cb4d04vllooh7tcbasyf3piapnix.png)
![0+2>-3(0)-3](https://img.qammunity.org/2019/formulas/mathematics/middle-school/810iwc6myda2em7pdn02pjn9ivv048qwc9.png)
True
So we shade the part that contains (0,0)
option D is correct graph