Question

In simplest radical form what are the solutions to the quadratic equation 0=-3x^2-4x+5

Answer 1

This is a quadratic equation with coefficients a= -3, b= -4 and c= 5. Thus, the discriminant b^2-4ac is (-4)^2 - 4(-3)(-4) = 16-48 = 16(1-3) = 16(-2).

The solutions are
-(-4) plus or minus sqrt(discriminant)
x = ---------------------------------------------------
2(-3)
4 plus or minus sqrt(16[-2])
= -----------------------------------------
-6
4 plus or minus 4*i*sqrt[2]
= ---------------------------------------
-6

This reduces to:

-2 plus or minus i*2*sqrt[2]
x = -------------------------------------- (answers)
3

Answer 2

well first you have to find the solution, before you can put it in RADICAL FORM