Question

A stone is thrown vertically upwards with an initial velocity of 40 ms-1. Find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Answer 1

To find the maximum height we use the expression:
U²=2gh
Where u is the initial velocity,
g is gravitational field strength
h is the maximum height.
h=u²/2g
h=40²/20
=1600/20
=80m