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Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How many moles of NH3 can be produced from 19.0 mol of H2 and excess N2?
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Aug 3, 2019
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Consider the following balanced reaction between hydrogen and nitrogen to form ammonia:
3H2(g) + N2(g)→2NH3(g)
How many moles of NH3 can be produced from 19.0 mol of H2 and excess N2?
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Israkir
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Three moles of H2 produce 2 moles of NH3. Since the reactinng ratios are constant, then the ratio of hydrogen consumed:ammonia is 3:2
Mathematically, 3 Mol H2=2mol NH3
19 Molly H2=?
Cross-multiplying gives;
(19*2)/3=12.67 moles
Kevin Ortman
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Aug 7, 2019
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