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Write an equation of a line that is perpendicular -3x -6y=17, (6,3)

User Kissie
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1 Answer

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I'll assume that (6,3) at the end means we want the pependicular through (6,3)

The perpendicular is gotten by swapping the coefficients on x and y and negating one; it doesn't matter which. The point it goes through sets the constant straightforwardly:

6x - 3y = 6(6) - 3(3) = 27

6x - 3y = 27 is the perpendicular



User Frozenca
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