Question

A basket contains 11 pieces of fruit, 4 apples, 5 oranges, and 2 bananas. Jonas takes a piece of fruit at random from the basket, and then Beth takes a piece at random. What is the probability that Jonas will get an orange and Beth will get an apple?

Answer 1

So, the probability of Jonas getting an orange and Beth getting an apple is 2/11. How did I get this? You would need to multiply both probabilities that Jonas will get an orange (5/11) and Beth will get an apple (4/10 or 2/5) = 5/11 * 2/5 = 2/11. Hope this helped! (I am sorry if I am wrong...)

Answer 2

The probability that Jonas will get an orange and Beth will get an apple is:

`(2)/(11)`

Explanation:

A basket contains 11 pieces of fruit, 4 apples, 5 oranges, and 2 bananas.

Let A denote the event of Jonas getting an orange.

and B denote the event of Beth getting an apple.

Let P denote the probability of an event.

Hence,

`P(A)=(5)/(11)`

( Since there are 5 oranges out of a total of 11 oranges )

Also,

`P(B)=(4)/(10)`

( Since after removing one orange there will be one less fruit i.e. there will be total 10 pieces of fruit left out of which 4 are apple)

Hence, The required probability is:

`=(5)/(11)* (4)/(10)\\\\=(2)/(11)`