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(6a³-3b³)(4a²+5b²) help me please

User Davidshinn
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2 Answers

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So what we're going to do here is FOIL (first, inner, outer, last):


(6 a^(3)*4 a^(2))+ (6 a^(3)*5 b^(2))+(-3 b^(3)* 4 a^(2))+(-3 b^(3)*5 b^(2))

When we multiply exponents, and they have the same base (for example both have a or both have b), we add them. Let's simplify this expression:


24 a^(5) +30 a^(3) b^(2)+(-12 b^(3) a^(2))+(-15 b^(5))

Which can be further simplified to:


24 a^(5) +30 a^(3) b^(2)-12 b^(3) a^(2)-15 b^(5)
User Majid Hajibaba
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2 votes
send the question sentences.
User Bkilinc
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