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Jansen Price · Answer 1 · 2019-12-15T03:18:01+0000

Look at the picture.
Use the Pythagorean theorem:

$\left((1)/(2)b\right)^2+12^2=13^2\\\\(1)/(4)b^2+144=169\ \ \ |-144\\\\(1)/(4)b^2=25\ \ \ |\cdot4\\\\b^2=100\to b=√(100)\to b=10\ cm$
The area of the triangle:

$A_t=(10\cdot12)/(2)=60\ cm^2$
The area of the square:

$A_s=10^2=100\ cm^2$
The surface area of rectangular square pyramid:

$SA=4A_t+A_s\\\\SA=4\cdot60+100=340\ cm^2$

What is the surface area of a regular square pyramid with a slant height of 12 cm-example-1

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