Question

The volume of the tank is 1890 L, and the density of seawater is 1.03 g/cm3. What would be the mass of the water in the fish tank?

Answer 1

volume in cm³:

1890 * 1000 => 1890000 L

density = 1.03 g/cm³

Therefore:

mass = density * volume

mass = 1.03 * 1890000

mass = 1946700 g

Answer 2

The mass of the water in the fish tank is
`1.94* 10^6\ g`.

Step-by-step explanation:

Given that,

Volume of the tank,
`V=1890\ L=1.89* 10^6\ cm^3`

The density of seawater,
`d=1.03\ g/cm^3`

The density of any material is given by its mass per unit volume. Its relation is given by :

`d=(m)/(V)`

m is the mass of the water in the fish tank

`m=d* V\\\\m=1.89* 10^6* 1.03\\\\m=1.94* 10^6\ g`

So, the mass of the water in the fish tank is
`1.94* 10^6\ g`. Hence, this is the required solution.