find the probability of a point chosen at random being in the shaded area of the diagram at the right

Onkar asked Apr 19, 2023

488,914 views

1 vote

Onkar asked Apr 19, 2023

by Onkar

2.2k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

11 votes

Answer: 1/9

Explanation:

The area of the shaded region is
$(4/2)^2 \pi =4\pi$

The area of the entire circle is
$(6)^2 \pi=36\pi$

So, the probability is
$(4\pi)/(36\pi)=1/9$

3.3k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers