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the length of the rectangle is 3 ft less than double the width, the area of the rectangle is 44 ft squared. what is the length and the width?

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A=wl is the area of the rectangle but here’s a picture to show u this might help u with the length and width have a wonderful and nice day
the length of the rectangle is 3 ft less than double the width, the area of the rectangle-example-1
User Robotik
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We need to find the length, l, and the width, w. Let's set up the two equations with the information found in the question:

l = 2w - 3
w = w
A = 44
ft^(2)

We know that area is equal to length * width (
A=l*w), so let's substitute those values


A=l*w

A=(2w-3)*w

A=2 w^(2)-3w

And we know that the area is equal to
44 ft^(2):


44=2 w^(2)-3w

Now we set equal to 0 and factor in order to get w:


0=2 w^(2)-3w-44

0=(2w-11)(w+4)

Then we set each factor equal to zero and solve for w. We get the two values:


(11)/(2) and
-4 for w.

We know that the width cannot be negative, so we take the value that is positive,
(11)/(2)

So now we know that w =
(11)/(2), so we plug in this value into the equation for the length:


l=2w-3

l=2( (11)/(2))-3

l= (22)/(2)-3

l=11-3=8

So we now know that the length is 8, and the width is
(11)/(2)
.
User Endasan
by
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