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The coordinates of trapezoid EFGH are E(4, 6), F(2, 3), G(4, 2), and H(8, 4). The image of EFGH under dilation is E'F'G'H'.

If the coordinates of vertex G' are (2, 1), what are the coordinates of vertex H'?

User Bruinbrown
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1 Answer

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G'(2, 1) = (1/2)·G(4, 2)

The dilation factor is 1/2. Applying that to H, we get
(1/2)·H(8, 4) = H'(4, 2)
User Craig Graham
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