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What is the equation of the line that passes through (-3, -1) and has a slope of 2/5? Put your answer in slope-intercept form.

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Hi there!

The general formula of A line in slope-intercept form is the following:

y = mx + n

In this formula m represents the slope of the line. Therefore, we can conclude that m = 2/5.

y = (2)/(5) x + n

We also know that the line passes through the point (-3, -1) and we can therefore substitute this coordinate into the formula of the line.
x = -3 and y = -1


- 1 = (2)/(5) * - 3 + n

Multiply first.

- 1 = - 1(1)/(5) + n

And finally add 1 1/5 to both sides of the equation.

(1)/(5) = n

We can now switch sides.

n = (1)/(5)

Now we've found our value of n, which we can substitute into the formula of our line. Hence, in slope-intercept form, we find the following:

y = (2)/(5) x + (1)/(5)

User Maria Piaredryj
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