Question

You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t^2 + 541. What is the height of the rock after 2 seconds?

Answer 1

For this case we have the following equation:

`h = -16t ^ 2 + 541`
To answer the question, what we must do is evaluate the function for t = 2.
We have then:

`h = -16 (2) ^ 2 + 541`
Rewriting we have:

`h = -16 (4) + 541 h = -64 + 541 h = 477 feet`
Answer:
The height of the rock after 2 seconds is:

`h = 477 feet`