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Find the (real-valued) general solution to the differential equation. z′′+5z′=0

User Hmatar
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Try this solution:1. to make up the characteristic equation:α²+5α=0;
\left[\begin{array}{ccc} \alpha=0 \\ \alpha =-5\\\end{array}2. to make up the final answer:y=C₁+C₂e⁻⁵ˣ
User Michael Easter
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