For this case we have the following expression:
![√(10)^{(3)/(4)x}](https://img.qammunity.org/2019/formulas/mathematics/high-school/aijwu33wj4yle8b8gqmdn02m2rhmv8jp62.png)
By power properties, we can rewrite the square root as number 10 as a base and number 1/2 as an exponent.
We have then:
![(10^{(1)/(2)})^{(3)/(4)x}](https://img.qammunity.org/2019/formulas/mathematics/high-school/v41qxfbuafxu9ajtee9ud95f22rmcmqipp.png)
Then, Rewriting we have:
![10^{(3)/(8)x}](https://img.qammunity.org/2019/formulas/mathematics/high-school/e5gvli7gje19gy92u2a6y7ggtia10y6ipa.png)
finally by properties of radicals we have:
Answer:
option 4