To find the mass of NaOH produced from 1.20 x 10² grams of Na2O, calculate the moles of Na2O, use the stoichiometry of the reaction to find moles of NaOH, and then convert these moles to grams using the molar mass of NaOH (40.00 g/mol).
To calculate how many grams of NaOH are produced from 1.20 x 10² grams of Na2O, we need to follow these steps:
Write the balanced chemical equation for the reaction: Na2O + H2O → 2 NaOH.
Calculate the molar mass of Na2O (77.96 g/mol).
Calculate the moles of Na2O from the given mass (1.20 x 10² grams).
Use the mole ratio from the balanced equation to find moles of NaOH (since 1 mole of Na2O produces 2 moles of NaOH).
Finally, convert the moles of NaOH to grams using the molar mass of NaOH (40.00 g/mol).
Solution:
Given mass of Na2O is 1.20 x 10² grams.
Moles of Na2O = Given mass / Molar mass = 1.20 x 10² g / 77.96 g/mol.
Moles of NaOH = Moles of Na2O x 2.
Grams of NaOH = Moles of NaOH x Molar mass of NaOH = Moles of NaOH x 40.00 g/mol.
By performing these calculations, we can find the mass of NaOH produced from the given mass of Na2O.