Question

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?

Answer 1


`\bf C(\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{0}) \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-5)}{6-3}\implies \cfrac{0+5}{6-3}\implies \cfrac{5}{3} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{5}{3}(x-3)\implies y+5=\cfrac{5}{3}x-5 \\\\\\ y=\cfrac{5}{3}x-10\implies \stackrel{standard~form}{-\cfrac{5}{3}x+y=-10}`

Answer 2

Just see my atachment.