Question

Find the number of real number solutions for the equation. x^2+0x-1=0

Answer 1

`x^2+0x-1=0 \\ x^2-1=0\\ x^2=1\\ x=-1 \vee x=1`

Answer 2

x^2 + 0x - 1 = 0

x^2 - 1 = 0

This is a difference of two squares which factors into the product of a sum and a difference with the pattern: a^2 - b^2 = (a + b)(a - b).

(x + 1)(x - 1) = 0

x + 1= 0 or x - 1 = 0

x = -1 or x = 1

Answer: There are two real solutions.