Question

Let the sample space be upper s equals startset 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 endset. suppose the outcomes are equally likely. compute the probability of the event eequals​"an odd number less than 9​."

Answer 1

`|\Omega|=10\\ |A|=4\\\\ P(A)=(4)/(10)=(2)/(5)=40\%`

Answer 2

That looks like the natural numbers 1 through 10, so ten of them. An odd number less than nine is 1,3,5,7, four of them. If they're equally likely, our probability is


`p = \frac 4 {10} = \frac 2 5`