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Find all solutions of the equation in the interval [0,2π) sec(theta) +2=0

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I will first reveal the most obvious secret of trig: Most of the problems are 30/60/90 or 45/45/90 triangles of some sort.


\sec \theta + 2 = 0


(1 )/( \cos \theta) = -2


\cos \theta = - \frac 1 2

The rule to remember is
\cos x = \cos a has solutions


x = \pm a + 2 \pi k \quad integer
k

Continuing where we left off, a cosine of -1/2 is a 30/60/90 triangle in the second or third quadrant; we pick second, and a little thought tells us the angle is
120^\circ.


\cos \theta = - \frac 1 2


\cos \theta = \cos \frac {2\pi} 3


\theta = \pm \frac {2\pi} 3 + 2 \pi k \quad integer
k

In the range we want, that's
k=0 with the plus sign and
k=1 with the minus, so


\theta = \frac {2\pi} 3 or
-\frac {2\pi} 3 + 2 \pi = \frac{4 \pi} 3


\theta = \frac {2\pi} 3 or
\frac{4 \pi} 3
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