Question

2fe(no3)3 + 3na2co3 → fe2(co3)3 + 6nano3 how many moles of nano3 are produced when 1.0 moles of fe(no3)3 reacts with excess sodium carbonate?

Answer 1

2Fe(NO3)3 + 3Na2CO3 → Fe2(CO3)3 + 6NaNO3
2 mol 6 mol
1 mol 3 mol

3 mol NaNO3

Answer 2

number of moles of NaNo3 produced = 3 moles

Step-by-step explanation:

From the equation 2 moles of Iron (iii) nitrate reacted with 3 moles of sodium carbonate to form 1 mole of iron(iii) carbonate and 6 moles sodium trioxonitrate.

Check whether the equation is balanced

2fe(No3)3 + 3Na2co3 → fe2(co3)3 + 6NaNo3

The equation is balanced.

From the equation

2 moles of fe(No3)3 produces 6 moles of NaNo3

1 mole of fe(No3)3 will produce ?

cross multiply

number of moles of NaNo3 produced = 6/2

number of moles of NaNo3 produced = 3 moles