Question

Evaluate g(n-7) if g(x)= x^2-5/3x

A. n^2-14n+44/3n-7
B. (n^2-5/3n)-7
C. n^2-14n+44/3n-21
D. n^2-7/3n-63

Answer 1

You have function
`g(x)=x^2- (5)/(3) x`. To count
`g(n-7)` you have to substitute
`n-7` instead of x in the expression of g(x):

`g(n-7)=(n-7)^2- (5)/(3) (n-7)=n^2-14n+49- (5)/(3) n+ (5)/(3) \cdot 7=`

`=n^2+n(-14- (5)/(3) )+(49+(35)/(3) )=n^2- (47)/(3) n+ (182)/(3)`.