23.6k views
4 votes
Evaluate ∫ x cos 3x dx.

1 Answer

5 votes
This can be integrated using the method "integration by parts." The formula is

\int{u\,dv}=uv-\int{v\,du}

Here, it is convenient to assign

u=x\\v=(1)/(3)sin((3x))

Then you have

\int{(xcos(3x))}\,dx=(1)/(3)xsin((3x))-\int{((1)/(3)sin((3x)))}\,dx\\\\=(1)/(3)xsin((3x))+(1)/(9)cos((3x))
User Cce
by
8.0k points

No related questions found