Question

Is this the right answer don’t mind the work I did some in my head but is it right

Answer 1

`\bf 1(1)/(4)\implies \cfrac{5}{4}\quad therefore\quad 1(1)/(4)~:~8\implies \cfrac{5}{4}~:~8\implies \cfrac{\quad (5)/(4)\quad }{8}\implies \cfrac{5}{32}\\\\ -------------------------------\\\\ \stackrel{actual~width}{\cfrac{\quad (5)/(2)\quad }{W}=\cfrac{5}{32}}\implies \cfrac{5}{2W}=\cfrac{5}{32}\implies \cfrac{5\cdot 32}{2\cdot 5}=W\implies \boxed{16=W}`


`\bf \stackrel{actual~length}{\cfrac{\quad (25)/(4)\quad }{L}=\cfrac{5}{32}}\implies \cfrac{25}{4L}=\cfrac{5}{32}\implies \cfrac{25\cdot 32}{4\cdot 5}=L\implies \boxed{40=L} \\\\\\ \stackrel{\textit{area of the park}}{16\cdot 40\implies 640}\\\\ -------------------------------`


`\bf \stackrel{actual~diameter}{\cfrac{\quad (5)/(4)\quad }{d}=\cfrac{5}{32}}\implies \cfrac{5}{4d}=\cfrac{5}{32}\implies \cfrac{5\cdot 32}{4\cdot 5}=d \\\\\\ 8=d\implies 4=\stackrel{radius}{r} \\\\\\ \stackrel{\textit{area of the pond}}{\pi r^2\implies \pi 4^2\implies 16\pi }\quad \approx \quad 50.24`

Answer 2

Yeah
That's what I got