Question

How to find the equation for a circle in standard form when given points M(2,4) and N(9,4)

Answer 1

`\bf M(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad N(\stackrel{x_2}{9}~,~\stackrel{y_2}{4}) \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-4}{9-2}\implies \cfrac{0}{7}\implies 0 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=0(x-2)\implies y-4=0\implies y=4`