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write out the sum using the summation notation, assuming the suggested pattern continues. -10-2+6+14+...+110

User Apilat
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The answer is summation of the quantity negative ten plus eight n from n equals zero to fifteen

User Patrina
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The series is an arithmetic series with first term -10 and common difference (-2-(-10))=8. The general term a_n can be written as
a_n = -10 + 8(n-1)
or
a_n = -18+8n

The last term corresponds to
110 = -18+8n
128 = 8n
16 = n

So, the summation can be written as

S_(16)=\sum\limits_(n=1)^(16){(-18+8n)}
User Ata Mohammadi
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