94.4k views
2 votes
Calculate the mass of hcl required to prepare 2.5 liters of a 0.08 molar solution of hcl. 1 h 1.01 hydrogen 17 cl 35.45 chlorine

a. 3.2 grams

b. 4.5 grams

c. 7.3 grams

d. 11.4 grams

1 Answer

4 votes

(moles)/(volume)=C M_{}
CM=0.08M , V=2.5 Lit.⇒moles=0.2mol.
0.2molHCl × (35.45gCl+1.01gH)/(1mol HCl) =7.292gHClit's the choice c

User Kalkin
by
7.2k points