1 Answer

Latsha · Answer 1 · 2019-12-12T22:17:31+0000

Answer

B) ㏒₁₂(1/2) - (㏒₁₂8 + ㏒₁₂W)

Step-by-step explanation
The first law of logarithms is
㏒AB = ㏒A+㏒B
㏒(A/B) = ㏒A - ㏒B
With this laws we can simplify the expression given

㏒₁₂((1/2)/8W) =㏒₁₂(1/2) - ㏒₁₂8W
= ㏒₁₂(1/2) - (㏒₁₂8 + ㏒W)

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions