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Savanna · Answer 1 · 2019-07-18T23:54:53+0000

A line that is parallel would have the same slope, so you are looking at a slope of -7
Since we have the slope and a point which we want the equation to cross, just plug into the point-slope formula (conveniently named):
y- y_(1)=m(x-x_(1))

y-32=-7(x-(-5)) y-32=-7(x+5) y-32=-7x-35 y=-7x-3

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