Answer:
C. Plate1, Trial 3
Step-by-step explanation:
In a given data set, outliers are data points that lie very much above or way below the other values. Presence of outliers can skew a data set and can result in erroneous values for mean and standard deviation.
An outlier can be identified if its value is lower than:

or if it is higher than:

where Q1 = first quartile, Q3 = third quartile
IQR = interquartile range i.e. Q3-Q1
In the given example, consolidating the data from plate 1, 2, 3 and 4 as well as trials 1,2 and 3 gives a data set with essentially 12 values for the light intensity measured in lumens:
Data set showing the measured lumens:
3,4,5,5,5,6,6,7,7,7,8,13
The data set of 12 points can be divided into 2 halves:
3,4,5,5,5,6 and 6,7,7,7,8,13
The first quartile is the median of the upper half: Q1 =

The third quartile is the median of the lower half: Q3 =

IQR = Q3-Q1 = 7-5 = 2
Based on equation (1):

Based on equation(2):

Therefore, any point that is lower than 2 or higher than 10 is an outlier. In the given data set, there are no numbers lower than 2 however there is one value higher than 10. Hence, 13 is an outlier which is a data point in Plate 1, Trial 3.