Question

What is the value of 19+5a^4-3b^2 when a = 2 and b=4

Answer 1

Heya!!

★Answer★

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Given,

a=2

b=4

Now,

19+5a^4-3b^2

=19+{5×(2)^4-3×(4)^2}

=19+80-48

=51

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#Hope My Answer Helped (:

Answer 2

Hey!
All you want to do here is plug and solve.
19 + 5(2^4) - 3(4^2)
First you would do the exponents and then multiply by the 5 or 3 because of PEMDAS!
19 + 5*16 - 3*16
19+80-48
Combine!
Your answer is 51!
Hope this helps!