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What is the value of 19+5a^4-3b^2 when a = 2 and b=4
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Aug 23, 2019
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What is the value of 19+5a^4-3b^2 when a = 2 and b=4
Mathematics
middle-school
Sam Kellett
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Heya!!
★Answer★
______________________________
Given,
a=2
b=4
Now,
19+5a^4-3b^2
=19+{5×(2)^4-3×(4)^2}
=19+80-48
=51
______________________________
#Hope My Answer Helped (:
Fara
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Aug 25, 2019
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Fara
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Hey!
All you want to do here is plug and solve.
19 + 5(2^4) - 3(4^2)
First you would do the exponents and then multiply by the 5 or 3 because of PEMDAS!
19 + 5*16 - 3*16
19+80-48
Combine!
Your answer is 51!
Hope this helps!
Munkay
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Aug 28, 2019
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Munkay
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