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5 votes
Does anyone know this

Does anyone know this-example-1
User Maclir
by
7.4k points

2 Answers

5 votes
Hey!


The first step to solving this would be to cross multiply the fractions. So, when you set up your equation it would look something like the...

Original equation :

(8)/(x) = (20)/(10)

New Equation {Apply Fraction Cross Multiplication} :
8 · 10 = x · 20

Now we switch the sides of the equation to get the variable x on the left side, which is generally where we always want x.

Old Equation :
8 · 10 = x · 20

New Equation {Switched} :
x · 20 = 8 · 10

Now we'll multiply the numbers 8 and 10.

Old Equation :
x · 20 = 8 · 10

New Equation {Multiplyed Left Side of the Equation} :
x · 20 = 80

Next we'll divide both sides by 20 to get x on its own.

Old Equation :
x · 20 = 80

New Equation {Added Divide Both Sides} :

(x*20)/(20) = (80)/(20)

Now we'll solve the equation.

Old Equation :

(x*20)/(20) = (80)/(20)

Solution {Old Equation Solved} :
x = 4

So, this means that in the equation provided x = 4.

Hope this helps!


- Lindsey Frazier ♥
User Aystub
by
7.7k points
5 votes
I think it is C

cross multiply 8 and 10 divide by 20

User Jomaora
by
8.3k points

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