Question

What is the area of the composite figure?

Answer 1

Option A)
`(6\pi + 10)~ m^2`

Explanation:

We are given a composite figure. We have to find the area of the composite figure.

The area of figure =

`(1)/(2)(\text{Area of bigger circle - Area of inner circle}) + \text{Area of rectangle}`

`\text{\bold{Area of outer circle}} = \pi R^2\\\text{where R is the radius of outer circle}\\= \pi (4)^2 = 16\pi~ m^2\\\text{\bold{Area of inner circle}} = \pi r^2\\\text{where r is the radius of inner circle}\\= \pi (2)^2 = 4\pi~ m^2\\\text{\bold{Area of Rectangle}} = l* b\\\text{where l is the length and b is the breadth of the rectangle}\\= 5* 2 = 10~m^2`

`\text{Area of composite figure} = \\(1)/(2)(\text{Area of bigger circle - Area of inner circle}) + \text{Area of rectangle} = 8\pi - 2\pi + 10\\=(6\pi + 10)~ m^2`

Option A)
`(6\pi + 10)~ m^2`

Answer 2

A) (6π + 10) m^2

Explanation:

The area of the composite figure = (Bigger half circle - Smaller half circle) + Area of the rectangle

Area of half circle = (πr^2) /2

Area of a rectangle = length * width

= (π.4^2 / 2 - π(2)^2 / 2) + 5*2

= π (16/2 - 4/2) + 10

= π(8 - 2) + 10

= π6 + 10

Area of the composite figure = (6π + 10)m^2

Answer is A) (6π + 10) m^2

Hope this will helpful.

Thank you.