The graph of the function
![f(x) =-x^2-4x + 2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/cv1mu6bit2jgq8bza3zit5th8u8hqz3hld.png)
is parabola with branches going down in the negative direction of y-axis.
The vertex of parabola has coordinates:
![x_v=(-(-4))/(2\cdot(-1))=-2, \\ y_v=-(-2)^2-4\cdot (-2)+2=-4+8+2=6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/iiwvppb97mx082u65ti0f91j7jg6vtncdw.png)
Then you can conclude that all x are possible, that means that the dimain is
![x\in (-\infty,\infty)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7x6iq7tdgyi6mv9tcoq6952766r8ilr1ce.png)
and the maximum value of y is at the vertex, then the range is
![(-\infty,6]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/93v7u0uj3zb3pmo0vsho5z33hgdn71zhg1.png)
.The function is increasing for x<-2 and decreasing for x>-2 (since vertex is the maximum point).
When x=0, y=2.
Hence,
The domain is x ≤ –2 - false.
The range is y - true.
The function is increasing over the interval (–∞ , –2) - true.
The function is decreasing over the interval (−4, ∞) - false.
The function has a positive y-intercept - true.