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The time t required to drive a centain distance varies inversely with the speed r. If it takes 2 hours to drive the distance at 30 mines per hour how long will it take to drive the same distance at 50 miles per hour

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An inversely proportional equation for our set of circumstances looks like this:
t= (k)/(r). We have a t value of 2 and an r value of 30, so we will sub those values in and solve for k, the constant of variation.
2= (k)/(30). Multiply both sides by 30 to get that k = 60. Now we need to find t when r = 50. We can do this now because we have a value for k.
t= (60)/(50) and t = 1.2 hours.
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