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You exert 375 j to move a 45 kg object five meters how much force is required
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May 3, 2019
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You exert 375 j to move a 45 kg object five meters how much force is required
Physics
high-school
Frank LaRosa
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Frank LaRosa
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F=ma
W=F*distance
375J=(45kg)(a)(5m)
a=375/(45*5)
a=1.67m/s^2
F=ma = 45kg * 1.67m/s^2=75N
Or go straight there like this:
W=F*distance
375J=F(5m)
F=375J/5m
F=75N
Hope this helps. Thanks
Rob Watts
answered
May 9, 2019
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Rob Watts
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