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Two soccer players kick the same 1-kg ball at the same time in opposite directions. one kicks with a force of 20 n; the other kicks with a force of 12 n. what is the resulting acceleration of the ball, in m/s2.

User Ivesingh
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1 Answer

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We can solve the problem by using Newton's second law of motion:

\sum F = ma (1)
where
the term on the left is the resultant of the forces acting on an object
m is the mass of the object
a is the acceleration of the object

The mass of the ball in this problem is m=1 kg. Two forces are applied, in opposite directions, of 20 N and 12 N, therefore the resultant of the forces is

\sum F= 20 N-12 N=8 N

Therefore, we can rearrange eq.(1) and use these data to find the acceleration of the ball:

a= (\sum F)/(m)= (8 N)/(1 kg)=8 m/s^2
User Collin M
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