Question

What mass in grams of chlorine gas is contained in a 15.5 L tank at 25.5°C and 1.98 atm show all the work you solve this problem

Answer 1

PV=nRT
PV=(m/M)RT

m=MPV/RT

V= 15.5 L
T=25.5 +273 = 298.5 K
P=1.98 atm
M(Cl2) = 35.5*2 = 71 g/mol
R = 0.08206 L*atm/(K*mol)

m=MPV/RT
m=(71 g/mol*1.98 atm*15.5L)/(0.08206 L*atm/(K*mol)*298.5K)

m=89.0 g Cl2