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What are the solutions of x^2=19x +1

User Sureshhh
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1 Answer

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X2=19x+1
x2- 19x-1=0
D=b2-4ac =(19)^2 -4*1*(-1) =365
x1,2= -b+√D over 2A
x1= 19-√365 over 2
X2 = 19+ √ 365 over 2

User Friendzis
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