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A natural number from 1 to 10 is randomly chosen p(even or 7)

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The natural numbers from 1 to 10 are the positive integers from 1 to 10, so ten numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.

The numbers in that list that are either even or 7 are: 2, 4, 6, 7, 8, 10, or six of the numbers from the original list. That means the probability that a randomly chosen natural number between 1 to 10 is either even or seven is 6 over 10:

P(even \:or\: 7) = (6)/(10) = (3)/(5)

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Answer:
P(even \:or\: 7) = (3)/(5)
User Dave Wanta
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