The natural numbers from 1 to 10 are the positive integers from 1 to 10, so ten numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.
The numbers in that list that are either even or 7 are: 2, 4, 6, 7, 8, 10, or six of the numbers from the original list. That means the probability that a randomly chosen natural number between 1 to 10 is either even or seven is 6 over 10:
![P(even \:or\: 7) = (6)/(10) = (3)/(5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/u504o4on16kqz47xixc4m31kf0vamvjxua.png)
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Answer:
![P(even \:or\: 7) = (3)/(5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ie3b5d6m350ryphgqk9456xcgn4sjc0t9j.png)