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F(x)=x^2+10-3 written in vertex form is f(x) = (x+5)^2 -28
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F(x)=x^2+10-3 written in vertex form is f(x) = (x+5)^2 -28

User Umar Arshad
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So whats the question?:) The minimum value of this graph is -5, -28. I graphed it to be sure as well. 
User IObert
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