The correct answers for x would be
![(2 +/- √(15) )/(11)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ovvpfn4fihvzm9viy119iu3zalr3czrhxe.png)
.
In order to find this, we must first get the equation to equal 0. In order to do that, subtract 1 from each side to get the following.
11
![x^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/x18wowxes8du7ezs6fltwoqbv6i8lovbjg.png)
- 4x - 1 = 0
Knowing this we can now use the quadratic equation using a = 11, b = -4 and c = -1. The quadratic equation is below.
![\frac{-b +/- \sqrt{ b^(2) - 4ac} }{2a}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/t6laffw3p5uex1kvykhyx6lj8k643j6lba.png)
Now we can plug the values into the equation to solve.
![\frac{4 +/- \sqrt{ -4^(2) - 4(11)(-1)} }{2(11)}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/q5i3dt9ondx41f8pnch50ge4uof681pj9d.png)
Then simplify using the order of operations.
![(2 +/- √(15) )/(11)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ovvpfn4fihvzm9viy119iu3zalr3czrhxe.png)
.