Answer:
Number of Dinner Menu in the Restaurant = 4 =[1 appetizer+ 1 salad+ 1 main dish + 1 dessert]
Number of Different Appetizer = 6
Number of Different Salad =2
Number of Different Main Dishes = 3
Number of Different Desserts =4
Number of Different Dinner Outcomes
=[Choosing 1 appetizer among 6 appetizer] × [Choosing 1 Salad item among 2 salad Items] ×[Choosing 1 main Dish among 3 main Dishes] × [Choosing 1 dessert among 4 desserts]
=Order is not Important,so we will use the concept of combinatorics
![=_(1)^(6)\textrm{C}*_(1)^(2)\textrm{C}* _(1)^(3)\textrm{C} * _(1)^(4)\textrm{C}\\\\=6 * 2 * 3 * 4\\\\=144](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jmz5t3o0kb6p2cqh2vac109364veglmwrz.png)
So, Number of Possible Dinner Outcomes = 144