Question

The boiling point of an aqueous solution is 101.28 °c. what is the freezing point?

Answer 1

Answer : -4.65 °C

Explanation : On solving the sum w.r.t to water as the aqueous solvent in solution;
(101.28°C - 100°C) / (0.512 c/m) = 2.5 m,

Now, 2.5 m X (1.86 °C/m) = 4.65 °C which will be the change in temperature of the solution in °C;

To find the freezing point we have to get it subtracted by 0°C

0°C - 4.65°C = -4.65°C