Answer : 5.16 mol
Explanation :
I think that the question should be "How many moles of fluorine are contained in 115.6 L at STP?"Let's assume that the gas is an ideal gas.
1 mole of ideal gas has the volume as 22.4 L at STP (273 K , 1 atm)
The given volume is 115.6 L.
moles in 22.4 L of gas = 1 mol
moles in 115.6 L of gas = (1 mol x 115.6 L) / 22.4 L = 5.16 mol