Question

How many grams of Silicon (Si, 28.09 g/mol) are in a computer chip with 1.08 x 10^23 atoms of Si

Answer 1

1 mol of any particles - 6.02 *10²³

(1.08*10²³ * 1 mol)/(6.02*10²³) = 1.08*10²³/6.02*10²³ mol Si

(1.08*10²³/6.02*10²³) mol Si * 28.09 g/1mol = (28.09*1.08*10²³)/6.02*10²³ ≈
≈ 5.04 g Si

Answer 2

Answer: 5.04 grams

Explanation:

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadro's no}}`

For silicon:

Atoms of silicon given =
`1.08* 10^(23)`

Avogadro's number =
`6.023* 10^(23)`

Putting values in above equation, we get:

`\text{Moles of silicon}=(1.08* 10^(23))/(6.023* 10^(23))=0.18mol`

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles

1 mole of
`Si` weighs = 28.09 g

0.18 moles of
`Si` contains =
`(28.09)/(1)* 0.18=5.04g`

Thus the mass of silicon in a computer chip is 5.04 grams.