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I need to write an equation of a line that passes through the point (3,2) and is parallel to the line y=3x-4.

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The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

We have the line y = 3x - 4.

The parallel lines have the same slope. Therefore we have y = 3x + b.

Put the coordinates of the point (3, 2) to the equation:

2 = 3(3) + b

2 = 9 + b subtract 9 from both sides

-7 = b → b = -7

Answer: y = 3x - 7

User Davisca
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