Find the GCF of the monomials 27x^2 and 81x^5.

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asked Oct 26, 2019 94.2k views

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Find the GCF of the monomials 27x^2 and 81x^5.

Mathematics
high-school

Jammi asked

by Jammi

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1 Answer

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27x² and 81x⁵

81 = 27*3
x⁵ = x²x³

81x⁵ = 27*3*x²x³= (27x²)*3x³

We can see that 81x⁵=(27x²)*3x³ includes as a factor 27x²,
so GCF is 27x².

Nivcaner answered Oct 31, 2019

by Nivcaner

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